Solveeit Logo
Login

Question

Chemistry Question on Chemical Reactions

The correct order of leaving group ability in nucleophilic substitution reaction is

A

\ceBr−>Cl−>CH3CO2−>HO−>H−\ce{Br^{-} > Cl^{-} > CH3CO2^{-} > HO^{-} > H^{-} }

B

\ceH−>HO−>CH3CO2−>CI−>Br−\ce{H^{-} > HO^{-} > CH3CO2^{-} > CI^{-} > Br^{-} }

C

\ceBr−>CH3CO2−>Cl−>HO−>H−\ce{Br^{-} > CH3CO_2^{-} > Cl^{-} > HO^{-} > H^{-}}

D

\ceCH3CO2−>Br−>Cl−>HO−>H−\ce{CH3CO2^{-} > Br^{-} > Cl^{-} > HO^{-} > H^{-}}

Answer

\ceBr−>Cl−>CH3CO2−>HO−>H−\ce{Br^{-} > Cl^{-} > CH3CO2^{-} > HO^{-} > H^{-} }

Explanation

Solution

The leaving group ability decreases as the basicity of the nucleophile increases. Since the basicity increases in the order: Br−<Cl−<CH3COO−<HO−<H− {Br^{-} < Cl^{-} < CH3COO^{-} < HO^{-} < H^{-} }, therefore, their leaving group ability decreases in the reverse order, i.e., Br−>Cl−>CH3COO−>HO−>H− {Br^{-} > Cl^{-} > CH_3COO^{-} > HO^{-} > H^{-} }. Thus, option (a) is correct.