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Chemistry Question on Ionic Equilibrium In Solution

The correct order of increasing ionic radii is

A

Mg2+<Na+<F–<O2–<N3–Mg^{2+} < Na^+ < F^– < O^{2–} < N^{3–}

B

N3–<O2–<F–<Na+<Mg2+N^{3–} < O^{2–} < F^{–} < Na^{+} < Mg^{2+}

C

F–<Na+<O2–<Mg2+<N3–F^– < Na^+ < O^{2–} < Mg^{2+} < N^{3–}

D

Na+<F–<Mg2+<O2–<N3–Na^+ < F^– < Mg^{2+ }< O^{2–} < N^{3–}

Answer

Mg2+<Na+<F–<O2–<N3–Mg^{2+} < Na^+ < F^– < O^{2–} < N^{3–}

Explanation

Solution

For isoelectronic species

Ionic  radii∝(−)ve  charge(+)ve  chargeIonic \;radii∝ \frac{(-)ve \;charge}{(+)ve \;charge}

Hence, correct order of ionic radii is

Mg2+<Na+<F–<O2–<N3–Mg^{2+} < Na^+ < F^– < O^{2–} < N^{3–}