Question

The correct order of increasing bond angles in the following species is

• A. $Cl_2O < ClO_2 < ClO_2^-$
• B. $ClO_2 < Cl_2O < ClO_2^-$
• C. $Cl_2O < ClO_2^- < ClO_2$
• D. $ClO_2^- < Cl_2O < ClO_2$

Answer 1

Answer: (C)

$Cl_2O < ClO_2^- < ClO_2$

Answer 2

The correct order of increasing bond angles in the following species is

$Cl_2O < ClO_2^- < ClO_2$

This is because In $ClO _{2}^{-}$there are two lone pairs of electrons that repel each other due to which two oxygen atoms come closer leading to a decrease in bond angle. Therefore the bond angle in $ClO _{2}^{-}$is less than $118^{\circ}$ which is the bond angle in $ClO _{2}$ which has less number of electrons on chlorine.

Read more from chapter:Bond Parameters: Enthalpy, Bond Length, Order & Angle