Question

The correct order of hybridisation of the central atom in the following species $NH _{3},\left[ PtCl _{4}\right]^{2-}, PCl _{5}\left[ BCl _{4}\right]^{-}$

• A. $sp^{3},dsp^{2},dsp^{3},sp^{2}$
• B. $sp^{3},dsp^{2},sp^{3},sp^{3}$
• C. $sp^{3},dsp^{2},dsp^{3},sp^{3}$
• D. $sp^{3},sp^{2},dsp^{3},sp^{3}$

Answer 1

Answer: (C)

$sp^{3},dsp^{2},dsp^{3},sp^{3}$

Answer 2

$\left[ NH _{3}\right] \rightarrow$ Three bond pairs $+$ one lone pair $\rightarrow$ Tetrahedral $\rightarrow s p^{3}$ hybridisation.
$\left[ PtCl_{4}\right]^{2-} \rightarrow$ Four hybrid orbitals $\rightarrow$ square planar $\rightarrow d s p^{2}$ hybridisation.
$\left[ PCl _{5}\right] \rightarrow$ Five hybrid orbitals $\rightarrow$ trigonal bipyramid $\rightarrow d s p^{3}$ hybridisation.
$\left[ BCl _{4}\right]^{-} \rightarrow$ Four hybrid orbitals $\rightarrow$ tetrahedral $\rightarrow s p^{3}$ hybridisation.