Question

The correct order for bond angles is –

• A. $NO_{2}^{+} > NO_{2} > NO_{2}^{-}$
• B. $NO_{2}^{+} > NO_{2}^{-} > NO_{2}$
• C. $NO_{2} > NO_{2}^{-} > NO_{2}^{+}$
• D. $NO_{2}^{-} > NO_{2} > NO_{2}^{+}$

Answer 1

Answer: (A)

$NO_{2}^{+} > NO_{2} > NO_{2}^{-}$

Answer 2

Each has$sp^{2}$hybridization having one lone pair on N in $NO_{2}^{+}$, one lone pair and one unshared pair of electron on N in$NO_{2}$and two lone pair of electrons in $NO_{2}^{-}$. Thus bond angles are.

$NO_{2}^{+}$> $NO_{2}$ > $NO_{2}^{-}$:: $180^{0}$ > $132^{0}$> $115^{0}$