Solveeit Logo

Question

Question: The correct option(s) to distinguish nitrate salts of \(M{n^{ + 2}}\) and \(C{u^{ + 2}}\) taken sepa...

The correct option(s) to distinguish nitrate salts of Mn+2M{n^{ + 2}} and Cu+2C{u^{ + 2}} taken separately is/are:
This question has multiple correct options
(A) Mn+2M{n^{ + 2}} shows the characteristic green colour in the flame test.
(B) Only Cu+2C{u^{ + 2}} shows the formation of precipitate by passing H2S{H_2}S in an acidic medium.
(C) Only Mn+2M{n^{ + 2}} shows the formation of precipitate by passing H2S{H_2}S in a faintly basic medium.
(D) Cu+2/CuC{u^{ + 2}}/Cu has higher reduction potential than Mn+2/MnM{n^{ + 2}}/Mn (measured under similar conditions).

Explanation

Solution

Cu+2C{u^{ + 2}} and Mn+2M{n^{ + 2}} both give green colour in flame test. Cu+2C{u^{ + 2}} belongs to group-II of cationic radical will give ppt. of CusCus in acidic medium. Both ions form ppt. in the basic medium. Cu+2/CuC{u^{ + 2}}/Cu =+0.34V = + 0.34V (SRP) and Mn+2/Mn=1.18VM{n^{ + 2}}/Mn = - 1.18V (SRP).

Complete step by step solution:
A flame test is an analytical procedure in chemistry to detect the presence of certain elements, primarily metal ions, based on each element’s characteristic emission spectrum. Cu+2C{u^{ + 2}} and Mn+2M{n^{ + 2}} both give green colour in flame tests so we cannot distinguish between both ions.
H2S{H_2}S is passed through the solution in an acidic medium to precipitate the sulphides of group-II cations. Sparingly soluble sulphides Cu+2C{u^{ + 2}} ions by the passage of hydrogen sulphide through the acidic medium. So, statement (B) is correct.
Mn+2M{n^{ + 2}} does not show the formation of precipitate by passing H2S{H_2}S in a faintly basic medium. So, the statement (C) is not correct.
Cu+2/CuC{u^{ + 2}}/Cu =+0.34V = + 0.34V and Mn+2/Mn=1.18VM{n^{ + 2}}/Mn = - 1.18V. Hence, Cu+2/CuC{u^{ + 2}}/Cu has higher reduction potential than Mn+2/MnM{n^{ + 2}}/Mn. So, the statement (D) is correct.

Hence, the correct options are (B) and (D).

Note: The Ksp{K_{sp}} value of group-II sulphide is low in comparison to Ksp{K_{sp}} value of group-IV sulphides. Hence, they do not get precipitated in an acidic medium, where S2{S^{2 - }} ion concentration is quite low. The main purpose of flame test is to observe the characteristic colour produced by certain metallic ions when vaporized in a flame and then to identify an unknown metallic ion by means of its flame test.