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Question

Chemistry Question on Electrochemistry

The correct option(s) about entropy (S) is(are)
[R=[ R = gas constant, F=F = Faraday constant, T=T = Temperature ]]

A

For the reaction, M(s)+2H+(aq)H2(g)+M2+(aq)M (s)+2 H ^{+}(a q) \rightarrow H _2(g)+ M ^{2+}(a q), if dEcell dT=RF\frac{ dE _{\text {cell }}}{ dT }=\frac{ R }{ F }, then the entropy change of the reaction is RR (assume that entropy and internal energy changes are temperature independent).

B

The cell reaction, Pt(s)H2(g,1bar)H+(aq,0.01M)H+(aq,0.1M)H2(g,1bar)Pt(s)Pt (s)\left| H _2(g, 1 bar )\right| H ^{+}(a q, 0.01 M ) \| H ^{+}(a q, 0.1 M )\left| H _2(g, 1 bar )\right| Pt (s), is an entropy driven process.

C

For racemization of an optically active compound, ΔS>0\Delta S >0.

D

ΔS>0\Delta S >0, for [Ni(H2O)6]2++3en[Ni(en)3]2++6H2O\left[ Ni \left( H _2 O \right)_6\right]^{2+}+3 en \rightarrow\left[ Ni ( en )_3\right]^{2+}+6 H _2 O (where en == ethylenediamine).

Answer

The cell reaction, Pt(s)H2(g,1bar)H+(aq,0.01M)H+(aq,0.1M)H2(g,1bar)Pt(s)Pt (s)\left| H _2(g, 1 bar )\right| H ^{+}(a q, 0.01 M ) \| H ^{+}(a q, 0.1 M )\left| H _2(g, 1 bar )\right| Pt (s), is an entropy driven process.

Explanation

Solution

The correct options are
(B) The cell reaction, Pt(s)H2(g,1bar)H+(aq,0.01M)H+(aq,0.1M)H2(g,1bar)Pt(s)Pt (s)\left| H _2(g, 1 bar )\right| H ^{+}(a q, 0.01 M ) \| H ^{+}(a q, 0.1 M )\left| H _2(g, 1 bar )\right| Pt (s), is an entropy driven process.
(C) For racemization of an optically active compound, ΔS>0\Delta S >0.
(D) ΔS>0\Delta S >0, for [Ni(H2O)6]2++3en[Ni(en)3]2++6H2O\left[ Ni \left( H _2 O \right)_6\right]^{2+}+3 en \rightarrow\left[ Ni ( en )_3\right]^{2+}+6 H _2 O (where en == ethylenediamine).