Question

The correct geometry and hybridization for ${XeF_4}$ are

• A. octahedral, $sp^3d^2$
• B. trigonal bipyramidal, $sp^3d$
• C. planar triangle, $sp^3d^3$
• D. square planar, $sp^3d^2$

Answer 1

Answer: (D)

square planar, $sp^3d^2$

Answer 2

$XeF _{4}$ is $AB _{4} L _{2}$ in which the Xenon is bonded with four fluorine atoms with 4 sigma bonds and xenon has two lone pairs (4 sigma bonds and 2 lone pairs).
So, the hybridisation is $sp ^{3} d ^{2}$.
Geometry is octahedral and shape is square planar.