Question
Chemistry Question on Bohr's model of hydrogen atom
The correct decreasing order of energy for the orbitals having, following set of quantum numbers:
(A) n = 3, l = 0, m = 0
(B) n = 4, l = 0, m = 0
(C) n = 3, l = 1, m = 0
(D) n = 3, l = 2, m = 1
A
(D) > (B) > (C) > (A)
B
(B) > (D) > (C) > (A)
C
(C) > (B) > (D) > (A)
D
(B) > (C) > (D) > (A)
Answer
(D) > (B) > (C) > (A)
Explanation
Solution
The correct answer is (A)
Energy of an orbital is directly proportional to the (n + l) value
If n + l value is same then the orbital with lower value of 'n' will have lower energy.
∴ correct order of energy D > B > C > A