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Chemistry Question on Bond Parameters

The correct bond order in the following species is :

A

O2+<O2−<O22+{O_2^+ < O_2^- < O_2^{2+} }

B

O2−<O2+<O22+{O_2^- < O_2^+ < O_{2}^{2+} }

C

O22+<O2+<O2−{O_2^{2+} < O_2^+ < O_2^- }

D

O22+<O2−<O2+{O_2^{2+} < O_2^- < O_2^+ }

Answer

O2−<O2+<O22+{O_2^- < O_2^+ < O_{2}^{2+} }

Explanation

Solution

According to molecular orbital theory (MOT)
O2−O2+O2+2 No.ofe−171514 Bondorder1.52.53.0\begin{matrix}&O^{-}_{2}&O^{+}_{2}&O^{+2}_{2}\\\ No. of e^{-}&17&15&14\\\ Bond order&1.5&2.5&3.0\end{matrix}