Solveeit Logo
Login

Question

Physics Question on Magnetic Field Due To A Current Element, Biot-Savart Law

The correct Biot-Savart law in vector form is

A

dB⃗=μ04πI(dl⃗×r⃗)r2d \vec{B} = \frac{\mu_{0}}{4 \pi} \frac{I\left(d \vec{l} \times \vec{r} \right)}{r^{2}}

B

d B⃗=μ04πI(dl⃗×r⃗)r3d \, \vec{B} = \frac{\mu_{0}}{4 \pi} \frac{I\left(d \vec{l} \times \vec{r} \right)}{r^{3}}

C

d B⃗=μ04πIdl⃗r2d \, \vec{B} = \frac{\mu_{0}}{4 \pi} \frac{I d \vec{l} }{r^{2}}

D

d B⃗=μ04πIdl⃗r3d \, \vec{B} = \frac{\mu_{0}}{4 \pi} \frac{I d \vec{l} }{r^{3}}

Answer

d B⃗=μ04πI(dl⃗×r⃗)r3d \, \vec{B} = \frac{\mu_{0}}{4 \pi} \frac{I\left(d \vec{l} \times \vec{r} \right)}{r^{3}}

Explanation

Solution

Biot-Savart law in vector form is
dB→=μ04πIdl→×r⃗r3\overrightarrow{dB} = \frac{\mu_{0}}{4\pi} \frac{I \overrightarrow{dl} \times\vec{r}}{r^{3}}