Question

The corner points of feasible region determined by the system of linear constraints are (0, 3), (1, 1) and (3, 0). Let Z = px + qy where p, q > 0. The condition on p and q so that, minimum of Z occurs at (3, 0) and (1, 1) is :

• A. p = 2q
• B. $p=\frac{q}{2}$
• C. p = 3q
• D. p = q

Answer 1

Answer: (B)

$p=\frac{q}{2}$

Answer 2

The correct option is (B) :$p=\frac{q}{2}$.