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Question: The coordination number and the oxidation state of the element 'E' in the complex [E(en)2(C2O4)] NO2...

The coordination number and the oxidation state of the element 'E' in the complex [E(en)2(C2O4)] NO2 (when 'en' is ethylene diamine) are, respectively,

A

4 and 2

B

4 and 3

C

6 and 3

D

6 and 2

Answer

6 and 3

Explanation

Solution

Let oxidation state of E is x so x + (–2) + 0 = +1 or x = +3

Coordination number is number of s-bonds between metal ion and ligands. 'en' and 'ox' are bidentate ligands Thus ; coordination number of E = 4 + 2 = 6.