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Question: The coordinates of the point of contact of the tangent to the parabola y<sup>2</sup> = 16x, which is...

The coordinates of the point of contact of the tangent to the parabola y2 = 16x, which is perpendicular to the line

2x – y + 5 = 0 are-

A

(16, 16)

B

(16, –16)

C

(1, 4)

D

(1, –4)

Answer

(16, –16)

Explanation

Solution

y2 = 16x ...(1)

4a = 16 ̃ a = 4

2x – y + 5 = 0 ...(2)

A line is perpendicular to the line (2)

is ̃ x + 2y + l = 0 ...(3)

̃ m = – 12\frac{1}{2}

Now, line (3) touches the parabola (1), so coordinate of the point of contact is

̃ P(am2,2am)\left( \frac{a}{m^{2}},\frac{2a}{m} \right) = (16, –16)