Question

The coordinates of the join of trisection of the points

(­–2, 3), (3, –1) nearer to (–2, 3), is.

• A. $\left( - \frac{1}{3},\frac{5}{3} \right)$
• B. $\left( \frac{4}{3},\frac{1}{3} \right)$
• C. $\left( - \frac{3}{4},2 \right)$
• D. $\left( \frac{1}{3},\frac{5}{3} \right)$

Answer 1

Answer: (A)

$\left( - \frac{1}{3},\frac{5}{3} \right)$

Answer 2

C divides the line in the ratio 1 : 2, so coordinates of C will be $\left( - \frac { 1 } { 3 } , \frac { 5 } { 3 } \right)$,

which is the required point.