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Question

Mathematics Question on coordinates of a point in space

The coordinates of the circumcentre of the triangle with vertices (2,3),(4,1)(2, 3), (4, -1) and (4,3)(4, 3) are

A

(2, 3)

B

(1, 3)

C

(3, 1)

D

(3, 2)

Answer

(3, 1)

Explanation

Solution

Coordinates of A, B, Care (2, 3) (4, -1), (4, 3). respectively.
Slope m1m_1 of BC is 3(1)44= \frac{3 -(-1)}{4-4} =\infty
Slope m2m_2 of AC is 3342=0 \frac{3 -3}{4-2} = 0

ΔABC\therefore \:\:\:\Delta ABC is right angled at C (4, 3)
\therefore Circumcentre of ΔABC\Delta ABC is the mid-point of the hypotenuse AB which is
(4+22,312)\left( \frac{4 + 2}{2} , \frac{3 -1}{2} \right) i.e.., (3,1)(3,1)