Question

The conversion(s) that can be carried out by bromine in carbon tetrachloride solvent is/are

• A. PhCH=CHCH3$\rightarrow$PhCHBrCHBrCH3
• B.
• C. CH3CH2COOH$\rightarrow$CH3CHBrCOOH
• D.

Answer 1

Answer: (A), (D)

PhCH=CHCH3$\rightarrow$PhCHBrCHBrCH3

Answer 2

There are two common qualitative methods used to test for unsaturation in compounds: the reaction with bromine in carbon tetrachloride and the reaction with potassium permanganate. In both instances, a positive outcome is indicated by the fading of color in the reagent.

In the bromine in carbon tetrachloride test, alkenes containing carbon-carbon double bonds and alkynes featuring carbon-carbon triple bonds react with bromine, leading to the formation of dibromoalkanes and tetrabromoalkanes, respectively. This reaction consumes molecular bromine, causing its distinctive dark red-brown hue to vanish if bromine is not excessively added. The swift disappearance of the bromine color confirms the presence of unsaturation.

The second qualitative test, known as the Baeyer test, employs potassium permanganate. This test relies on the oxidation capability of potassium permanganate to convert carbon-carbon double bonds into alkanediols or carbon-carbon triple bonds into carboxylic acids, thereby identifying unsaturation.

It's worth noting that only ethene gas exhibits positive results for both tests, while ethane does not display these reactions.

The correct answer is option(s):
(A): PhCH=CHCH3$\rightarrow$PhCHBrCHBrCH3
(D):