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Chemistry Question on Aldehydes, Ketones and Carboxylic Acids

The conversion of propan−1−olpropan-1-ol to n−butylaminen-butylamine involves the sequential addition of reagents. The correct sequential order of reagents is

A

(i)SOCl2(ii)KCN(iii)H2/Ni,Na(Hg)/C2H5OH(i) SOCl_2 (ii) KCN (iii) H_2/Ni, Na(Hg)/C_2H_5OH

B

(i)HCl(ii)H2/Ni,Na(Hg)/C2H5OH(i) HCl (ii) H_2/Ni, Na(Hg)/C_2H_5OH

C

(i)SOCl2(ii)KCN(iii)CH3NH2(i) SOCl_2 (ii) KCN (iii) CH_3NH_2

D

(i)HCl(ii)CH3NH2(i) HCl (ii) CH_3NH_2

Answer

(i)SOCl2(ii)KCN(iii)H2/Ni,Na(Hg)/C2H5OH(i) SOCl_2 (ii) KCN (iii) H_2/Ni, Na(Hg)/C_2H_5OH

Explanation

Solution

i SOCl2 ii KCN iii H2/Ni, NaHg/C2H5OH

Hence, the correct option is (A): (i) SOCl2SOCl_2 (ii) KCNKCN (iii) H2/NiH_2/Ni, Na$$(Hg)/C_2H_5OH