The conjugate of (x = 0,y = \frac{3 + 7i}{2i}) in the form o... | MATH - CONJUGATE, MODULUS AND ARGUMENT OF COMPLEX NUMBERS | SolveeIt

The conjugate of $x = 0,y = \frac{3 + 7i}{2i}$ in the form of a + ib, is.

$\frac{1 + 2i}{1 - i}$

$\frac{1}{1 - \cos\theta + i\sin\theta}$

$(a + ib) < (c + id)$

$a^{2} + b^{2} = 0$

Answer

$(a + ib) < (c + id)$

Explanation

$z = \frac { ( 2 + i ) ^ { 2 } } { 3 + i }$ $z^{3} = (3 + 5i)^{3} = 3^{3} + (5i)^{3} + 3.3.5i(3 + 5i) = - 198 + 10i$

Conjugate $z^{3} + \bar{z} + 198 = 10i - 198 + 3 - 5i + 198 = 3 + 5i$ .

Question: The conjugate of \(x = 0,y = \frac{3 + 7i}{2i}\) in the form of a + ib, is....