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Question: The conjugate acid of \(H{S^ - }\) is. A. \({S^{2 - }}\). B. \({H_2}S\). C. Both A and B. D....

The conjugate acid of HSH{S^ - } is.
A. S2{S^{2 - }}.
B. H2S{H_2}S.
C. Both A and B.
D. None of the above.

Explanation

Solution

We know that the Bronsted-Lowry theory of acid and base. According to this theory an acid is a proton donor while the base is a proton acceptor. The proton is represented by the symbol H+{H^ + } and we know that the conjugate acid is a cation and conjugate base is an anion.

Complete step by step answer: The Bronsted-Lowry theory is based on an acid and base reaction.
We know that, an acid is a species which has the capacity of donating a proton that is hydrogen ion is called Bronsted-Lowry acid and a base is species which has the capacity of accepting proton and a base it needs to have a lone pair of electrons on the base which bonds to the hydrogen ion.
Now, we see Conjugate acid.
According to Bronsted-Lowry theory the conjugate acid is the chemical species which is formed after the base accepts the hydrogen atom is called conjugate acid.
Acid+BaseConjugateBase+ConjugateAcidAcid + Base \rightleftharpoons Conjugate\,Base + Conjugate\,Acid
Apply the Bronsted-Lowry theory to find the conjugate acidHSH{S^ - }.
Hydrogen sulfuric acid dissociated into hydrogen sulfate ion. The conjugate acid of the hydrogen sulfate ion is the hydrogen sulfuric acid.
HS(aq)+H2O(l)H2S(aq)+OH(aq)H{S^ - }\left( {aq} \right) + {H_2}O\left( l \right) \rightleftharpoons {H_2}S\left( {aq} \right) + O{H^ - }\left( {aq} \right)
In the above reaction HSH{S^ - } acts as Bronsted-Lowry base which accepts hydrogen atom from its conjugate acidH2S{H_2}S.

So, the correct answer is “Option B”.

Note: We must know that a conjugate acid contains one hydrogen atom in addition and positive charge than the base from which is formed. A conjugate base has one hydrogen atom less and negative charge than the acid from which it is formed.
Example: Carbonic acid and hydronium ions are formed by the reaction of bicarbonate ions with the water.