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Question

Chemistry Question on Acids and Bases

The conjugate acid and base of HPO42 {HPO^{2-}_{4}} respectively are

A

\cePO43\ce{PO^{3-}_{4}} and \ceH2PO4\ce{H_2 PO^{-}_{4}}

B

\ceH2PO4\ce{H_2 PO^{-}_{4}} and \cePO43\ce{PO^{3-}_{4}}

C

\ceH3PO4\ce{H_3 PO_{4}} and \cePO43\ce{PO^{3-}_{4}}

D

\ceH2PO4\ce{H_2 PO^{-}_{4}} and \ceH2PO4\ce{H_2PO_{4}}

Answer

\ceH2PO4\ce{H_2 PO^{-}_{4}} and \cePO43\ce{PO^{3-}_{4}}

Explanation

Solution

{\underset{\text{Acid}}{ {HPO^{2-}_4}}+H+> + H^+ ->\underset{\text{Conjugate base}}{ {PO^{3-}_4}} }
{\underset{\text{Base}}{ {HPO^{2-}_4}}+H+> + H^+ ->\underset{\text{Conjugate acid}}{ {H_2PO^-_4}} }