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Question

Physics Question on Electric Current

The conductivity of a superconductor is

A

Infinite

B

Very large

C

Very small

D

Zero

Answer

Infinite

Explanation

Solution

Resistance of 1m length wire will be R=40×10−8×18×10−6=5×10−2 ΩR =40 \times 10^{-8} \times \frac{1}{8 \times 10^{-6}} = 5 \times 10^{-2} \, \Omega ΔVΔx=5×10−2×0.2=10−2\frac{\Delta V}{\Delta x} = 5 \times 10^{-2} \times 0.2 = 10^{-2} V/m