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Question

Chemistry Question on Electrochemistry

The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 Scm-1 . Calculate its molar conductivity.

Answer

Given, κκ = 0.0248 S cm-1 c
= 0.20 M

∴ Molar conductivity, = m=κ×1000c\land_m =\frac{\kappa\times1000}{c}

= 0.0248×10000.2\frac{0.0248 \times 1000}{0.2}

=124 Scm2mol-1