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Question: The compressibility of water is \(4 \times 10 ^ { - 5 }\) per unit atmospheric pressure. The decreas...

The compressibility of water is 4×10−54 \times 10 ^ { - 5 } per unit atmospheric pressure. The decrease in volume of 100 cubic centimeter of water under a pressure of 100 atmosphere will be

A

0.4 cc

B

4×10−5cc4 \times 10 ^ { - 5 } c c

C

0.025 cc

D

0.004 cc

Answer

0.4 cc

Explanation

Solution

C=1K=ΔV/VΔPC = \frac { 1 } { K } = \frac { \Delta V / V } { \Delta P }⇒ ΔV=C×ΔP×V\Delta V = C \times \Delta P \times V

=4×10−5×100×100=0.4cc= 4 \times 10 ^ { - 5 } \times 100 \times 100 = 0.4 c c