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Question: The compressibility of water \[4 \times {10^{ - 5}}\]per unit atmospheric pressure. What will be the...

The compressibility of water 4×1054 \times {10^{ - 5}}per unit atmospheric pressure. What will be the decrease in volume of 100100 cubic centimeter of water under the pressure of 100100 atmosphere?

Explanation

Solution

In order to solve this question, we are going to firstly consider all the values as given in the question, then, the formula for the compressibility of a liquid is taken containing the change in pressure and volume terms, then, putting the values in the equation, the decrease in the volume is found.

Formula used: The compressibility of water is given by the formula
C=ΔVVΔPC = \dfrac{{\Delta V}}{V} \cdot \Delta P
Where, ΔV\Delta Vis the change in the volume,VVis the total volume of water andΔP\Delta Pis the change in the pressure.

Complete step-by-step solution:
In the above question, we can see that
The compressibility of water is given equal to
C=4×105C = 4 \times {10^{ - 5}}per unit atmospheric pressure,
The total volume of the water is given equal to:
V=100CCV = 100CC
The pressure of the water is given as:
P=100atmP = 100atm
Now, the compressibility of water is given by the formula
C=ΔVVΔPC = \dfrac{{\Delta V}}{V} \cdot \Delta P
Putting the values as given in the question in above equation,

4×105=ΔV100×100 ΔV=4×105  4 \times {10^{ - 5}} = \dfrac{{\Delta V}}{{100}} \times 100 \\\ \Rightarrow \Delta V = 4 \times {10^{ - 5}} \\\

Hence, the volume of the water has decreased by4×1054 \times {10^{ - 5}} cubic centimeter of water.

Note: In thermodynamics and fluid mechanics, the compressibility is a measure of the relative volume change of a fluid or solid as a response to a pressure change. Hence, knowing the pressure change in a system and the total volume of the system, the change in the volume can be found and the compressibility here is referring to the decrease in the volume of water.