The compressibility factor ((Z)) of one mole of a van der Wa... | Chemistry | SolveeIt

Question

The compressibility factor $(Z)$ of one mole of a van der Waals gas of negligible $�a�$ value is

$1$

$\frac{bp}{RT}$

$1+\frac{bp}{RT}$

$1-\frac{bp}{RT}$

Answer

$1+\frac{bp}{RT}$

Explanation

Solution

van der Waals' equation is
$\left(p+\frac{a}{V^{2}}\right)(V-b)=R T\,\,\,$ (for 1 mole)
If $a$ is negligible, $p+\frac{a}{V^{2}} \approx p$
$p(V-b)=R T$
$\Rightarrow p V-p b=R T$
or $\frac{p V}{R T}-\frac{p b}{R T}=1$
$\Rightarrow \frac{p V}{R T}=1+\frac{p b}{R T}$

Chemistry Question on Van Der Waals equation

Solution