Question

The compressibility factor for a real gas is expressed by, z = 1 + $\frac { \mathrm { BP } } { \mathrm { RT } }$ The value of B at 500 K and 600 bar is 0.0169 L/mol. Therefore the molar volume of the gas at 500 K and 600 bar is–

• A. 0.1 L
• B. 9 × 10–5 L
• C. 8.62 × 10–2 L/mol
• D. 1.65 L

Answer 1

Answer: (C)

8.62 × 10–2 L/mol

Answer 2

Z = 1 + $\frac { 0.0169 \times 600 } { 0.083 \times 500 }$ = 1.244

\ V_m = $\frac { 1.244 \times 0.083 \times 500 } { 600 }$or

V_m = 8.6 × 10^–2 L