Question
Question: The compounds A, B and C in the following reaction sequence are 3PO4, the ester of phosphoric acid. With PCl3, we get ester of phosphoric acid, (C6H5)3PO3.
However, the yield of chlorobenzene is very small and the main product is triphenyl phosphate, which is mainly formed by the reaction between phenol and PCl3
There is a reduction reaction of phenol with zinc dust, the product formed are benzene and ZnO. The reaction can be given as follow:
C6H5OH+Zn→C6H6+ZnO
When phenol is reacted with acetyl chloride in the presence of sodium hydroxide, it leads to the formation of phenyl esters and this reaction will lead to the formation of phenyl ethanoate. This reaction shows the acidic nature of phenol.
Hence, the compounds A, B and C in the above reaction sequence are Triphenyl phosphate, benzene, phenyl acetate respectively.
Therefore, the correct answer is option (B).
Note: The yield of the reaction in phenol with zinc dust for the formation of benzene is lower. Homolytic fission is the splitting of the pair of electrons between two separated atoms. It is a reduction reaction of phenol to benzene by the zinc dust. So, zinc is the reducing agent. Benzene formed is volatile in nature and it can be separated by fractional distillation.