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Chemistry Question on Haloalkanes and Haloarenes

The compound without a chiral carbon atom is:

A

BrCH2CHCH3 ∣ CH2BrBrC{{H}_{2}}\overset{\begin{smallmatrix} C{{H}_{3}} \\\ | \end{smallmatrix}}{\mathop{CH}}\,C{{H}_{2}}Br

B

C2H5CH2CHCH3 ∣ CH2Br{{C}_{2}}{{H}_{5}}C{{H}_{2}}\overset{\begin{smallmatrix} C{{H}_{3}} \\\ | \end{smallmatrix}}{\mathop{CH}}\,C{{H}_{2}}Br

C

C3H2CH∣ CH3 CH2Br{{C}_{3}}{{H}_{2}}\underset{\begin{smallmatrix} | \\\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,C{{H}_{2}}Br

D

HOOCCCH3 ∣∣ CH3 CHCOOHHOOC\underset{\begin{smallmatrix} | \\\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\\ | \end{smallmatrix}}{\mathop{C}}}\,CHCOOH

Answer

BrCH2CHCH3 ∣ CH2BrBrC{{H}_{2}}\overset{\begin{smallmatrix} C{{H}_{3}} \\\ | \end{smallmatrix}}{\mathop{CH}}\,C{{H}_{2}}Br

Explanation

Solution

A chiral carbon atom is that whose all the four valencies are satisfied by different atoms or groups. In the alternate (a), two valencies are satisfied by the same group i. e., −CH2Br-C{{H}_{2}}Br So, the compound without a chiral carbon atom is
CH3 ∣ BrCH2CHCH2Br \begin{aligned} & C{{H}_{3}} \\\ & | \\\ & BrC{{H}_{2}}CHC{{H}_{2}}Br \\\ \end{aligned}