Question

The compound that does not produce nitrogen has by the thermal decomposition is:
A.$N{{H}_{4}}N{{O}_{2}}$ $N{{H}_{4}}N{{O}_{2}}$
B.${{(N{{H}_{4}})}_{2}}S{{O}_{4}}$
C.$Ba{{({{N}_{3}})}_{2}}$
D.${{(N{{H}_{4}})}_{2}}C{{r}_{2}}{{O}_{7}}$

Answer 1

thermal decomposition reaction is a type of decomposition reaction which takes place in presence of heat. We will check the thermal decomposition reactions of all the above options and will get our answer.

Complete step by step solution:
The first option is Ammonium Nitrate with a chemical formula of$N{{H}_{4}}N{{O}_{2}}$. It is a crystalline solid consisting of ammonium ions and nitrate ions. It is highly soluble in water and is hygroscopic.
The thermal decomposition reaction of $N{{H}_{4}}N{{O}_{2}}$is as follows:
$N{{H}_{4}}N{{O}_{2}}\,\xrightarrow{\Delta }\,{{N}_{2}}\,+\,2{{H}_{2}}O$
It yields nitrogen and water respectively.
The second option is Ammonium Sulphate with a chemical formula of${{(N{{H}_{4}})}_{2}}S{{O}_{4}}$. It is an inorganic sulphate salt. It has a high melting point and is soluble in water.
The thermal decomposition reaction of ammonium sulphate is as follows:
${{(N{{H}_{4}})}_{2}}S{{O}_{4}}\,\xrightarrow{\Delta }\,2N{{H}_{3}}\,+\,{{H}_{2}}S{{O}_{4}}$
It yields ammonia and sulphuric acid. No nitrogen is released in the above reaction.
In the third option we are given Barium Azide with a chemical formula of$Ba{{({{N}_{3}})}_{2}}$. It is an inorganic azide which is explosive in nature like other azides. The thermal decomposition barium azide is as follows:
$Ba{{({{N}_{3}})}_{2\,}}\,\xrightarrow{\Delta }\,Ba\,+\,3{{N}_{2}}$
It yields barium and nitrogen gas.
The next option is Ammonium Dichromate. It is also an inorganic compound. In this compound chromium has +6 oxidation state which is known as hexavalent chromium.
The thermal decomposition of ammonium dichromate is as follows:
${{(N{{H}_{4}})}_{2}}C{{r}_{2}}{{O}_{7}}\,\xrightarrow{\Delta }\,{{N}_{2\,}}\,+\,C{{r}_{2}}{{O}_{3}}\,+\,4{{H}_{2}}O$
It yields nitrogen gas, chromium oxide and water.
Out of all the following options only Ammonium sulphate does not produce nitrogen gas on heating. Rest all produces nitrogen gas on heating.

So the correct option is B.${{(N{{H}_{4}})}_{2}}S{{O}_{4}}$.

Note:
This is a question from p-block inorganic chemistry. If one learns the preparation methods of nitrogen then this question can easily be solved as all the other options are preparation methods of nitrogen.