Question

The compound that does not liberate $C{{O}_{2}}$ on treatment with aqueous sodium bicarbonate solution, is:
a.) Benzoic acid
b.) Benzenesulfonic acid
c.) Salicylic acid
d.) Carbolic acid (phenol)

Answer 1

Sodium bicarbonate is a chemical compound which is made up of carbon, sodium, oxygen and hydrogen. Sodium bicarbonate is a monosodium salt of the carbonic acid, it is a white crystalline odorless and has a bitter taste.

Complete step by step answer:
To solve this question first we have to understand the decomposition of sodium bicarbonate:
Sodium carbonate decomposes to give sodium ions and bicarbonate ions. The reaction involved is shown below:
$NaHC{{O}_{3}}\rightleftharpoons N{{a}^{+}}+HC{{O}_{3}}^{-}$

Now the bicarbonate ion produced will decompose by the acid present and release carbon dioxide. The reaction involved is shown below:
$HC{{O}_{3}}^{-}+{{H}^{+}}\to {{H}_{2}}O+C{{O}_{2}}$

This reaction takes place only when the acid present is stronger than the bicarbonate ion.
Here carbolic acid i.e. phenol is less acidic than bicarbonate ion hence it will not produce carbon dioxide.
So, the correct answer is “Option D”.

Additional Information:
Uses of sodium bicarbonate:
Sodium carbonate or baking soda is a versatile compound. It is quite cheap because it is used in common household substances.
Sodium bicarbonate is used in medicines as an antacid. The 5 percent sodium bicarbonate infusion injection is given during the medical emergencies.
Sodium carbonate is also used at home to raise the batter of flour. It is also used to make baking powder which is a mixture of baking soda and a mild acid.

Note: Sodium bicarbonate is produced on a large scale by reacting the cold and concentrated solution of the brine which is sodium chloride with ammonia and carbon dioxide. This is the Solvay process which is used for the production of sodium bicarbonate.