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Question

Chemistry Question on Stoichiometry and Stoichiometric Calculations

The composition of a sample of wustite is Fe0.93OFe _{0.93} O. What percentage of the iron is present in the form of Fe (III)?

A

5%5\%

B

7.08%7.08\%

C

15.05%15.05\%

D

23.6%23.6\%

Answer

15.05%15.05\%

Explanation

Solution

In pure iron oxide (FeO)(FeO), iron and oxygen are present in the ratio 1:11: 1. However, here number of Fe2+Fe ^{2+} present =0.93=0.93 Or No. of Fe2+Fe ^{2+} ions missing =0.07=0.07 Since each Fe2+Fe ^{2+} ion has 22 positive charge, the total number of charge due to missing (0.07)Fe2+( 0.07 ) Fe ^{2+} ions =0.07×2=0.14=0.07 \times 2=0.14 To maintain electrical neutrality, 0.140.14 positive charge is compensated by the presence of Fe3+Fe ^{3+} ions. Now since, replacement of one Fe2+Fe ^{2+} ion by one Fe3+Fe ^{3+} ion increases one positive charge, 0.140.14 positive charge must be compensated by the presence of 0.14Fe3+0.14 \,Fe ^{3+} ions. In short, 0.93Fe2+0.93\, Fe ^{2+} ions have 0.14Fe3+0.14\, Fe ^{3+} ions 100Fe2+100 \,Fe ^{2+} ions have =0.140.93×100=15.05%=\frac{0.14}{0.93} \times 100=15.05 \%