Solveeit Logo

Question

Question: The complex showing a spin-only magnetic moment of 2.83BM is: (A) \(Ni{{(CO)}_{4}}\) (B) \({{[N...

The complex showing a spin-only magnetic moment of 2.83BM is:
(A) Ni(CO)4Ni{{(CO)}_{4}}
(B) [Ni(Cl)4]2{{[Ni{{(Cl)}_{4}}]}^{2-}}
(C) Ni(PPh3)4Ni{{(PP{{h}_{3}})}_{4}}
(D) [Ni(CN)4]2{{[Ni{{(CN)}_{4}}]}^{2-}}

Explanation

Solution

Synthesis of early understandings of chemical bond formation by valence bond theory. To explain the nature of bonding in coordination compounds is the Valence Bond theory (VB), which theory explains the structure and magnetic properties of coordination compounds. The structure of and bond linkages of coordination compounds are easily explained with the help of the Valence Bond theory.

Complete step by step answer:
Postulates of valence bond theory of coordination compounds:
(i) The central metal ion of a suitable number of atomic orbitals are hybridized to provide empty hybrid orbitals.
(ii) The ligands which are donated electron pairs to these empty hybrid orbitals and are directed towards the positions of ligands according to the geometry of the complex.
(iii) (n-1) d orbitals which are known as inner d-orbitals used in hybridization, then the complex is called inner orbital or spin complex.
(iv) When the coordination compounds with one or more unpaired electrons d-orbital, is said to be paramagnetic.
Spin only magnetic moment of complex compounds will be calculated by the expression,
μ=n(n+2)\mu =\sqrt{n(n+2)}
Where n= number of unpaired electrons and the value of spin-only magnetic moment units in BM

Ion/complexConfigurationThe oxidation state of metalNo of unpaired electrons (n)Spin-only magnetic momentμ=n(n+2)\mu =\sqrt{n(n+2)}
Ni(CO)4Ni{{(CO)}_{4}}4s23d84{{s}^{2}}3{{d}^{8}} (strong field ligand)000 BM
[Ni(Cl)4]2{{[Ni{{(Cl)}_{4}}]}^{2-}}4s23d84{{s}^{2}}3{{d}^{8}} (weak field ligand)+22μ=n(n+2)=2(2+2)=2.83BM\mu =\sqrt{n(n+2)}=\sqrt{2(2+2)}=2.83BM
Ni(PPh3)4Ni{{(PP{{h}_{3}})}_{4}}4s23d84{{s}^{2}}3{{d}^{8}} (strong field ligand)000 BM
[Ni(CN)4]2{{[Ni{{(CN)}_{4}}]}^{2-}}4s23d84{{s}^{2}}3{{d}^{8}} (strong field ligand)000 BM

Hence, the complex showing a spin-only magnetic moment of 2.83BM is [Ni(Cl)4]2{{[Ni{{(Cl)}_{4}}]}^{2-}}
So, the correct answer is “Option B”.

Note: According to valence band theory, there are two types of ligands- strong field ligands and weak field ligands. A ligand that is capable of forcing the electrons of a central metal ion or atom or complex to pair up is a strong field ligand and weak field ligand is not capable of making electrons of metal ions or atoms to pair up.