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Question

Mathematics Question on complex numbers

The complex number z=z+iyz = z + iy which satisfies the equation z3iz+3i=1\left| \frac{z-3i}{z+3i}\right| = 1 , lies on

A

the X-axis

B

the straight line y = 3

C

a circle passing through origin

D

None of the above

Answer

the X-axis

Explanation

Solution

z3iz+3i=1\left| \frac{z-3i}{z+3i}\right| = 1
z3i=z+3i\Rightarrow \left|z-3i\right| = \left|z+3i\right|
[if zz1=z+z2| z-z_1 |=| z + z_2 | ,
then it is a perpendicular bisector of z1z_1 and z2z_2]
Hence, perpendicular bisector of (0,3)(0, 3) and (0,3)(0, - 3) is X-axis.