The complex formed when (Al\_2O\_3) is leached from Bauxite... | Chemistry | SolveeIt

Question

The complex formed when $Al_2O_3$ is leached from Bauxite using concentrated NaOH solution is,

$Na[Al(OH)_4]$

$NaAl_2O_4$

$Na_2[Al(OH)_3]$

$Na_2AlO_2$

Answer

$Na[Al(OH)_4]$

Explanation

Solution

When bauxite $\left( Al _{2} O _{3}\right)$ is leached by $NaOH$ , it gives $Na \left[ Al ( OH )_{4}\right]$ , soluble in $NaOH$ 'Thus, used to remove impurities.

$Al _{2} O _{3}(8)+2 NaOH (a q)+3 H _{2} O \longrightarrow 2 NaAl \left( OH _{4}\right)^{1}(a q)$

Chemistry Question on Concentration of ores

Solution