Question

The combustion of glucose takes place according to the equation:$\text{C}_6\text{H}_{12}\text{O}_6 + 6\text{O}_2 \rightarrow 6\text{CO}_2 + 6\text{H}_2\text{O}, \Delta H = -72 \text{ k-cal}$The energy required for the combustion of 1.6 g of glucose is

• A. 0.064 k-cal
• B. 0.64 k-cal
• C. 6.4 k-cal
• D. 64 k-cal

Answer 1

Answer: (B)

0.64 k-cal

Answer 2

The correct option is (B):0.64 k-cal