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Question

Mathematics Question on measurement of angles

The combined equation of the two lines ax+by+c=0a x+b y+c=0 and ax+by+c=0a^{\prime} x+b^{\prime} y+c^{\prime}=0 can be written as (ax+by+c)(ax+by+c)=0(a x+b y+c)\left(a^{\prime} x+b^{\prime} y+c^{\prime}\right)=0
The equation of the angle bisectors of the lines represented by the equation 2x2+xy3y2=02 x^2+x y-3 y^2=0 is

A

3x2+5xy+2y2=03 x^2+5 x y+2 y^2=0

B

x2y210xy=0x^2-y^2-10 x y=0

C

3x2+xy2y2=03 x^2+x y-2 y^2=0

D

x2y2+10xy=0x^2-y^2+10 x y=0

Answer

x2y210xy=0x^2-y^2-10 x y=0

Explanation

Solution

Equation of the pair of angle bisector for the homogenous equation ax2+2hxy+by2=0 is given as
a−bx2−y2​=hxy​
Here a=2,h=1/2&b=−3
Equation will become
2−(−3)x2−y2​=1/2xy​
x2−y2=10xy
x2−y2−10xy=0