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Question: The colour of ammonium phosphomolybdate is: (A) Green (B) yellow (C) Blue (D) Colourless...

The colour of ammonium phosphomolybdate is:
(A) Green
(B) yellow
(C) Blue
(D) Colourless

Explanation

Solution

Ammonium phosphomolybdate is an inorganic salt and it contains phosphomolybdate ion complexes. It is widely used for estimation of PO43PO_4^{ - 3} in soil and also in analytical estimation. The reaction involved in the preparation of ammonium phosphomolybdate is very important to solve this question.

Complete step by step solution:
Ammonium phosphomolybdate is an inorganic ammonium salt. The chemical formula of ammonium phosphomolybdate is (NH4)3.PO4.12MoO4{(N{H_4})_3}.P{O_4}.12Mo{O_4}.
Preparation of Ammonium phosphomolybdate:
1. The phosphate of metals such as calcium is heated with concentrated nitric acid to produce calcium nitrate and phosphoric acid.
Ca2(PO4)2+6HNO33Ca(NO3)2+2H3PO4C{a_2}{(P{O_4})_2} + 6HN{O_3} \to 3Ca{(N{O_3})_2} + 2{H_3}P{O_4}
2. Ammonium molybdate is heated in excess of concentrated nitric acid and phosphoric acid to yield ammonium phosphomolybdate.
12(NH4)2MoO4+21HNO3+H3PO4(NH4)3PO4.12MoO3+12H2O+21NH4NO312{(N{H_4})_2}Mo{O_4} + 21HN{O_3} + {H_3}P{O_4} \to {(N{H_4})_3}P{O_4}.12Mo{O_3} + 12{H_2}O + 21N{H_4}N{O_3}
Ammonium molybdate [(NH4)3MoO4{(N{H_4})_3}Mo{O_4}] is a white solid and the ammonium phosphomolybdate is obtained as a yellow precipitate. It is used for estimation of PO43PO_4^{ - 3} in a given analytical experiment and in soil.
Therefore, from the above discussion, it is evident that ammonium phosphomolybdate is yellow in colour. Thus Option B is the correct answer.
Additional information: The preparation of ammonium arsenomolybdate (NH4)2.AsO4.12MoO3{(N{H_4})_2}.As{O_4}.12Mo{O_3} is same as the preparation of ammonium phosphomolybdate but, there is a small change is that instead of H3PO4{H_3}P{O_4}, arsenic acid (H3AsO4{H_3}As{O_4}).
12(NH4)2.MoO4+H3AsO4+21HNO3(NH4)3.AsO4.12MoO3+12H2O+21NH4NO312{(N{H_4})_2}.Mo{O_4} + {H_3}As{O_4} + 21HN{O_3} \to {(N{H_4})_3}.As{O_4}.12Mo{O_3} + 12{H_2}O + 21N{H_4}N{O_3}
The ammonium arsenate phosphate also gives out the yellow precipitate. It is also used to estimate AsO43AsO_4^{ - 3}.

Hence, the answer is option (B).

Note: The chemical formula of ammonium phosphomolybdate is (NH4)3.PO4.12MoO4{(N{H_4})_3}.P{O_4}.12Mo{O_4} whereas, the chemical formula of ammonium arsenomolybdate is (NH4)2.AsO4.12MoO3{(N{H_4})_2}.As{O_4}.12Mo{O_3}. Ammonium phosphomolybdate is used for estimation of PO43PO_4^{ - 3} and ammonium arsenomolybdate is used for estimation of AsO43AsO_4^{ - 3}. Both Ammonium phosphomolybdate and ammonium arsenomolybdate are compounds of ammonium molybdate.