Question
Question: The coercivity of a small magnet where the ferromagnet gets demagnetized is \(3 \times {10^3}A{m^{-1...
The coercivity of a small magnet where the ferromagnet gets demagnetized is 3×103Am−1. The current required to be passed in a solenoid of length 10cm and number of turns 100, so that the magnet gets demagnetized when inside the solenoid is
a. 30mA
b. 60mA
c. 3A
d. 6A
Solution
We have a solenoid of length 10cm having 100 number of turns. A small magnet having a coercivity of 3×103Am−1. We have to find the current required to be passed through the solenoid so that the magnet will get demagnetized when it is placed inside the solenoid.
Complete step by step answer:
The particular intensity of the magnetic field at which the magnet is demagnetized is called the coercivity of the magnet.
The coercivity of the magnet can be written as,
H=μ0B
For a solenoid, the magnetic field will be,
B=μ0nI
where B is the magnetic field, n is the number of turns per unit length, μ0 is the permeability of free space, and I is the current through each turn,
∴μ0B=H=nI
The coercivity of the small magnet is given by
H=3×103Am−1
The length of the solenoid is given by,
L=10cm=0.1m
The number of turns of the solenoid is given by,
N=100
The number of turns per unit length can be written as,
n=0.1100
From this we get,
I=nH
It is given that, H=3×103Am−1 and n=0.1100
Substituting the values in the above equation, we get
I=0.11003×103=100300=3A
Therefore the current required to be passed in a solenoid of length 10cm and number of turns 100, so that the magnet gets demagnetized when inside the solenoid is 3A.
Hence, the correct answer is option (C).
Note: A solenoid is a long closely wound helical coil. The magnetic moment per unit volume of a material is defined as the intensity of magnetization. Ferromagnetic substances are substances that are strongly magnetized in the presence of a magnetic field. The material will be magnetized in the direction of the magnetic field.