Question
Mathematics Question on Binomial theorem
The coefficient of x5 in the expansion of (2x3−3x21)5 is
A
8
B
9
C
980
D
326
Answer
980
Explanation
Solution
The correct answer is (C) : 980
The coefficient of x5 in the expansion of (2x3−3x21)5 is
8
9
980
326
980
The correct answer is (C) : 980