Question
Question: The coefficient of \(x\) in the expansion of \(\left( {1 + x} \right)\left( {1 + 2x} \right)\left(...
The coefficient of x in the expansion of (1+x)(1+2x)(1+3x).....(1+100x) is –
(A) 5050
(B) 10100
(C) 5151
(D) 4950
Solution
Series – An expression of the form x1+x2+x3......,where x1,x2,x3......, is a sequence of numbers is called a series. Coefficient is a numerical or constant quantity placed before and multiplying the variable in an algebraic expression.
Complete step by step answer:
(1+x)(1+2x)(1+3x).....(1+100x)
We are required to find the coefficient of x in the above expansion.
Now, first, multiply the first two terms
(1+x)(1+2x)=1+x+2x+2x2
⇒1+x(1+2)+2x2
Similarly, multiply the first three terms
\Rightarrow \left( {1 + x} \right)\left( {1 + 2x} \right)\left( {1 + 3x} \right) \\\
\Rightarrow \left( {1 + x + 2x + 2{x^2}} \right)\left( {1 + 3x} \right){\text{ }}\left[ {{\text{from previous multiplicaiton we can write}}\left( {1 + x} \right)\left( {1 + 2x} \right)} \right] \\\
\Rightarrow 1 + x + 2x + 2{x^2} + 3x + 3{x^2} + 6{x^2} + 6{x^3}\left[ { = \left( {1 + x + 2x + 2{x^2}} \right)} \right] \\\
\Rightarrow 1 + \left( {x + 2x + 3x} \right) + 2{x^2} + 3{x^2} + 6{x^2} + 6{x^3} \\\
\Rightarrow 1 + x\left( {1 + 2 + 3} \right) + 11{x^2} + 6{x^3} \\\
So, in the expansion of (1+x)(1+2x)(1+3x).....(1+100x) coefficient of x should be (1+2+3+.....+100). We know that the sum of the first ′n′ natural numbers is given by the expression 2n(n+1).
∴ The coefficient of x in the above expression is =2100(100+1)
= \dfrac{{100 \times 101}}{2} \\\
= 5050 \\\
_∴ The correct answer is option (A) 5050. _
Note: Here students must take care of the concept of series. Students made a mistake during the multiplication. They think that in a series there are so many terms, how will we multiply them. So, they should be aware about a series and their properties.