Solveeit Logo

Question

Mathematics Question on binomial expansion formula

The coefficient of x20x^{20} in the expansion of (1+x2)40.(x2+2+1x2)5(1 + x^2)^{40} . (x^2 + 2 + \frac{1}{x^2})^{-5} is

A

30C10^{30}C_{10}

B

30C25^{30}C_{25}

C

11

D

None of these

Answer

30C25^{30}C_{25}

Explanation

Solution

Expression = =(1+x2)40.(x+1x)10= \left(1+x^{2}\right)^{40} .\left(x+\frac{1}{x}\right)^{-10}
=(1+x2)30.x10=\left(1+x^{2}\right)^{30} .x^{10}
The coefficient of x20x^{20} in x10(1+x2)30x^{10}\left(1+x^{2}\right)^{30}
== the coefficient of x10x^{10} in (1+x2)30\left(1+x^{2}\right)^{30}
=30C5=30C305=30C25= \,^{30} C_{5} =\,^{30}C_{30-5} = \,^{30}C_{25}