Question
Mathematics Question on Differential equations
The coefficient of x 101 in the expression (5 + x)500 + x(5 + x)499 + x 2(5 + x)498 + ……+ x 500, x > 0, is
A
501 C 101 (5)399
B
501 C 101 (5)400
C
501 C 100 (5)400
D
500 C 101 (5)399
Answer
501 C 101 (5)399
Explanation
Solution
The correct option is(A): 501 C 101 (5)399
Coeff. of x101 in xx+5−1x500[(xx+5)501−1]
= Coeff. of x101 in 51[(x+5)501−x501]
=51501c101.5400
=501C101.5399