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Question

Mathematics Question on Differential equations

The coefficient of x 101 in the expression (5 + x)500 + x(5 + x)499 + x 2(5 + x)498 + ……+ x 500, x > 0, is

A

501 C 101 (5)399

B

501 C 101 (5)400

C

501 C 100 (5)400

D

500 C 101 (5)399

Answer

501 C 101 (5)399

Explanation

Solution

The correct option is(A): 501 C 101 (5)399

Coeff. of x101 in x500[(x+5x)5011]x+5x1\frac{x_{500}[(\frac{x+5}{x})^{501}-1]}{\frac{x+5}{x}-1}

= Coeff. of x101 in 15[(x+5)501x501]\frac{1}{5}[(x+5)^{501-x^{501}}]

=15501c101.5400=\frac{1}{5}^{501}c_{101}.5^{400}

=501C101.5399=501C_{101}.5^{399}