Question

The coefficient of static friction, ${{\mu }_{s}},$ between block $A$ of mass $2 \,kg$ and the table as shown in the figure, is $0.2$. What would be the maximum mass value of block $B$ so that the two blocks do not move ? The string and the pulley are assumed to be smooth and massless $(g=10\,m/{{s}^{2}})$

• A. 2.0 kg
• B. 4.0 kg
• C. 0.2 kg
• D. 0.4 kg

Answer 1

Answer: (D)

0.4 kg

Answer 2

Key Idea : The tension in the string is equal to static frictional force between block $A$ and the surface. Let the mass of the block $B$ is $M$.