Question

The coefficient of static friction, $\mu _ { s }$ between block A of mass 2 kg and the table as shown in the figure is 0.2. What would be the maximum mass value of block B so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless. $\left( g = 10 m / s ^ { 2 } \right)$

• A. 2.0 kg
• B. 4.0 kg
• C. 0.2 kg
• D. 0.4 kg

Answer 1

Answer: (D)

0.4 kg

Answer 2

$\mu _ { s } = \frac { m _ { B } } { m _ { A } }$ ⇒ $0.2 = \frac { m _ { B } } { 2 }$ ⇒ $m _ { B } = 0.4 \mathrm {~kg}$