Question
Physics Question on thermal properties of matter
The coefficient of linear expansion of brass and steel rod are ‘α1’ and ‘α2’ respectively. Lengths of brass and steel rods are ‘l1’ and‘l2’ respectively. If (l2 - l1) is maintained same at all temperatures, which one of the following relation is correct?
α1l2 = α2l1
l1α1=l2α2
α1l22=α2l12
α12l2=α22l1
l1α1=l2α2
Solution
Let's consider the relation between the change in length (Δl) and the original length (l) for each rod:
For the brass rod, we have:
Δl1 = α1 x l1 x ΔT
For the steel rod, we have:
Δl2 = α2 x l2 x ΔT
Here, ΔT represents the change in temperature.
Given that (l2 - l1) is maintained the same at all temperatures, we can equate the changes in length:
Δl1 = Δl2
Substituting the expressions for Δl1 and Δl2 from above:
α1 x l1 x ΔT = α2 x l2 x ΔT
The ΔT cancels out from both sides, giving us:
α1l1 = α2l2
Therefore, the correct relation is option (B): l1α1 = l2α2