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Question: The coefficient of apparent expansion of a liquid when determined using two different vessels A and ...

The coefficient of apparent expansion of a liquid when determined using two different vessels A and B are γ1{\gamma _1}and γ2{\gamma _2} respectively. If the coefficient of linear expansion of the vessel A is α\alpha , the coefficient of linear expansion of the vessel B is
(A) αγ1γ2γ1+γ2\dfrac{{\alpha {\gamma _1}{\gamma _2}}}{{{\gamma _1} + {\gamma _2}}}
(B) γ1γ22α\dfrac{{{\gamma _1} - {\gamma _2}}}{{2\alpha }}
(C) γ1γ2+α3\dfrac{{{\gamma _1} - {\gamma _2} + \alpha }}{3}
(D) γ1γ23+α\dfrac{{{\gamma _1} - {\gamma _2}}}{3} + \alpha

Explanation

Solution

Hint
Since the given liquid is same, we know that coefficient of real expansion (γreal)\left( {{\gamma _{real}}} \right) is equal for the same liquid i.e., γreal=γapp+αv{\gamma _{real}} = {\gamma _{app}} + {\alpha _v} ; where αv{\alpha _v} is coefficient of volume expansion . So, we equal the coefficients of real expansions for the two vessels and find the coefficient of linear expansion of the vessel B.

Complete step by step answer
Now, For vessel A,
γAreal=γ1+αvA{\gamma _A}_{real} = {\gamma _1} + {\alpha _{vA}}
Since, αvA=3α{\alpha _{vA}} = 3\alpha
γAreal=γ1+3α\Rightarrow {\gamma _A}_{real} = {\gamma _1} + 3\alpha …(i)
And for vessel B
γBreal=γ2+αvB\Rightarrow {\gamma _{Breal}} = {\gamma _2} + {\alpha _{vB}}
Since, αvB=3αB{\alpha _{vB}} = 3{\alpha _B}
γBreal=γ2+3αB\Rightarrow {\gamma _B}_{real} = {\gamma _2} + 3{\alpha _B} …(ii)
Where, αB{\alpha _B} is coefficient of linear expansion of the vessel B.
Now, we equal the coefficients of real expansions for the two vessels
From (i) and (ii), we get
γ2+3αB=γ1+3α{\gamma _2} + 3{\alpha _B} = {\gamma _1} + 3\alpha
3αB=γ1γ2+3α\Rightarrow 3{\alpha _B} = {\gamma _1} - {\gamma _2} + 3\alpha
αB=γ1γ2+3α3\Rightarrow {\alpha _B} = \dfrac{{{\gamma _1} - {\gamma _2} + 3\alpha }}{3}
αB=γ1γ23+α\Rightarrow {\alpha _B} = \dfrac{{{\gamma _1} - {\gamma _2}}}{3} + \alpha
Therefore, the coefficient of linear expansion of the vessel (B) is γ1γ23+α\dfrac{{{\gamma _1} - {\gamma _2}}}{3} + \alpha
Hence, option (D) is correct.

Note
Here the coefficient of real expansion is same and it is the sum of coefficient of apparent expansion and the coefficient of volume expansion but not the coefficient of linear expansion and the relation between coefficient of linear expansion and coefficient of volume expansion is αv=3α{\alpha _v} = 3\alpha