Question

The coagulation of 200 mL of a positive colloid took place when 0.73 g HCl was added to it without changing the volume much. The flocculation value of HCl for the colloid is

• A. 100
• B. 36.5
• C. 0.365
• D. 150

Answer 1

Answer: (A)

100

Answer 2

200 mL of the sol required = 0.73 g HCl
$= \frac{0.73}{36.5}=$ 0.02 mol mmol
$\therefore$ $\quad$ 1000 mL (1 L) of the sol will require
$= \frac{20}{200}$ ? 1000 = 100 mmol
Thus, the flocculation value of HCl for the colloid is 100.