Question

The co-ordination number and the oxidation state of the element $'M'$ in the complex $[ M(en)_{2}(C_{2}O_{4})]NO_{2}$ \\{ where (en) is ethane-1,2-diamine) are, respectively

• A. $6$ and $3$
• B. $6$ and $2$
• C. $4$ and $2$
• D. $4$ and $3$

Answer 1

Answer: (A)

$6$ and $3$

Answer 2

The correct option s(A): 6 and 3.

For the given coordinate compound.

$[M (en)_2 (C_2O_4)]NO_2$

(i) $\because$ All the (3) ligands are bi dented thus its coordinate number $=6$

(ii) Oxidation number of $M$ will be

$x+0+2 \times(-2)=0-1$
$\therefore \,x$ (oxidation number of $M)= 3$