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Question: The co-ordinates of points \(A , B , C , D\) are (a, 2, 1), (1, –1, 1), (2, – 3, 4) and (a+1, a+2, ...

The co-ordinates of points A,B,C,DA , B , C , D are (a, 2, 1), (1, –1, 1), (2, – 3, 4) and (a+1, a+2, a+3) respectively. If AB=5A B = 5and CD=6C D = 6, then a=a =

A

2

B

3

C

– 2

D

– 3

Answer

– 3

Explanation

Solution

AB=(a1)2+32+0=5A B = \sqrt { ( a - 1 ) ^ { 2 } + 3 ^ { 2 } + 0 } = 5 a1=±4\Rightarrow a - 1 = \pm 4 a=3,5\Rightarrow a = - 3,5

CD=(a1)2+(a+5)2+(a1)2=6C D = \sqrt { ( a - 1 ) ^ { 2 } + ( a + 5 ) ^ { 2 } + ( a - 1 ) ^ { 2 } } = 6

a22a15=0a=3,5\Rightarrow a ^ { 2 } - 2 a - 15 = 0 \Rightarrow a = - 3,5

But common solution of (i) and (ii) is – 3.